56x=x^2+196

Solution for 56x=x^2+196 equation:

56x=x^2+196

We move all terms to the left:

56x-(x^2+196)=0

We get rid of parentheses

-x^2+56x-196=0

We add all the numbers together, and all the variables

-1x^2+56x-196=0

a = -1; b = 56; c = -196;
Δ = b2-4ac
Δ = 562-4·(-1)·(-196)
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-28\sqrt{3}}{2*-1}=\frac{-56-28\sqrt{3}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+28\sqrt{3}}{2*-1}=\frac{-56+28\sqrt{3}}{-2}
$